v) 2e^(x) is a particular integral for y'-y=2e^(x) . True or false
Solution.
"y'-y=2e^x."Сompose and solve the characteristic equation:
"\\lambda-1=0, \\newline\n\\lambda=1."
Therefore, "y=Ce^{\\lambda x}=Ce^x," where "C" is some constant, is the general solution of the equation.
If "C=2," then "y=2e^x" is a particular integral, a solution of the equation.
Answer. Yes.
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