Question #169232

find the differential equation 𝑦=2A𝑥^4+4B𝑥^3−6C𝑥^2+5D𝑥 +11E


1
Expert's answer
2021-03-09T14:47:58-0500

𝑦=(2A𝑥4+4B𝑥36C𝑥2+5D𝑥+11E)=(2A𝑥4)+(4B𝑥3)(6C𝑥2)+(5D𝑥)+(11E)=8Ax3+12Bx212Cx+5D.𝑦'=(2A𝑥^4+4B𝑥^3−6C𝑥^2+5D𝑥 +11E)'=\\(2A𝑥^4)'+(4B𝑥^3)'−(6C𝑥^2)'+(5D𝑥 )'+(11E)'=\\8Ax^3+12Bx^2-12Cx+5D.


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