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Answer to Question #169232 in Differential Equations for Love Ng
Question #169232
find the differential equation 𝑦=2A𝑥^4+4B𝑥^3−6C𝑥^2+5D𝑥 +11E
Expert's answer
"\ud835\udc66'=(2A\ud835\udc65^4+4B\ud835\udc65^3\u22126C\ud835\udc65^2+5D\ud835\udc65 +11E)'=\\\\(2A\ud835\udc65^4)'+(4B\ud835\udc65^3)'\u2212(6C\ud835\udc65^2)'+(5D\ud835\udc65 )'+(11E)'=\\\\8Ax^3+12Bx^2-12Cx+5D."
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