Question #168583

(3x^2y^3e^x+y^3+y^2)DX+(x^2y^3e^x-xy)sy=0


1
Expert's answer
2021-03-12T01:29:55-0500

(3x2y3ex+y3+y2)dx+(x2y3exxy)dy=0M(x,y)=3x2y3ex+y3+y2N(x,y)=x2y3exxyMy=9x2y2ex+3y2+2yNx=2xexy3yMyNxMyNxNM=9x2y2ex+3y2+3y2xexy32x2y3exxyy3y2(3x^2y^3e^x+y^3+y^2)dx+(x^2y^3e^x-xy)dy=0\\ M(x,y)=3x^2y^3e^x+y^3+y^2\\ N(x,y)=x^2y^3e^x-xy\\ \frac{\partial M}{\partial y}=9x^2y^2e^x+3y^2+2y\\ \frac{\partial N}{\partial x}=2xe^xy^3-y\\ \frac{\partial M}{\partial y}\neq \frac{\partial N}{\partial x}\\ \frac{\frac{\partial M}{\partial y}-\frac{\partial N}{\partial x}}{N-M}=\frac{9x^2y^2e^x+3y^2+3y-2xe^xy^3}{-2x^2y^3e^x-xy-y^3-y^2}\\


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