Solution.
dx3d3y+4dxdy=x+3cosx+e−2x. This is a linear differential equation of the third-order with constant coefficients. The general solution of this equation is found as the sum of the general solution y~ of the corresponding homogeneous equation and some particular integral solution y∗ of the inhomogeneous equation: y=y~+y∗.
Сompose and solve the characteristic equation:
λ3+4λ=0,λ(λ2+4)=0,λ1=0,or λ2+4=0, λ2=2i, λ3=−2i.
Therefore, y~=C1eλ1x+C2eaxcosbx+C3eaxsinbx,
where a - real part, and b - imaginary part of a complex number λ2 and λ3. So,
y~=C1+C2cos2x+C3sin2x. The particular integral solution y∗ write in the form:
y∗=y1+y2+y3. Since the right-hand side contains a cosx , we look for a particular integral solution y1 in the form:
y1=Acosx+Bsinx. Using the method of indefinite coefficients we find that A=0 and B=1. So, y1=sinx.
Since the right-hand side also contains a e−2x , we find a particular integral solution y2 in the form:
y2=Ce−2x.Using the method of indefinite coefficients we find that C=−161.
Therefore, y2=−161e−2x.
The number is characteristic, so y3 is written as
y3=x(Dx+E). Using the method of indefinite coefficients we find that D=81 and E=0. So, y3=x(81x+0)=81x2.
As follows, the particular integral solution of dx3d3y+4dxdy=x+3cosx+e−2x is
y∗=sinx−161e−2x+81x2, and the general solution of the same equation is
y=C1+C2cos2x+C3sin2x+sinx−161e−2x+81x2. Answer.
y∗=sinx−161e−2x+81x2, where y∗ is the particular integral solution.
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