Question #16068

how to differentiate x = L sin Ɵ/2 + L/2 sin Ɵ/2

Expert's answer

How to differentiate x=Lsin(θ2)+L/2sin(θ2)x = L\sin \left(\frac{\theta}{2}\right) + L / 2\sin \left(\frac{\theta}{2}\right)

Solution:


x=Lsin(θ2)+L/2sin(θ2)=32Lsin(θ2)x = L \sin \left(\frac {\theta}{2}\right) + L / 2 \sin \left(\frac {\theta}{2}\right) = \frac {3}{2} L \sin \left(\frac {\theta}{2}\right)dxdθ=3212Lcos(θ2)=34Lcos(θ2)\frac {d x}{d \theta} = \frac {3}{2} \cdot \frac {1}{2} L \cos \left(\frac {\theta}{2}\right) = \frac {3}{4} L \cos \left(\frac {\theta}{2}\right)


Answer: dxdθ=34Lcos(θ2)\frac{dx}{d\theta} = \frac{3}{4} L\cos \left(\frac{\theta}{2}\right)

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