How to differentiate x=Lsin(θ2)+L/2sin(θ2)x = L\sin \left(\frac{\theta}{2}\right) + L / 2\sin \left(\frac{\theta}{2}\right)x=Lsin(2θ)+L/2sin(2θ)
Solution:
Answer: dxdθ=34Lcos(θ2)\frac{dx}{d\theta} = \frac{3}{4} L\cos \left(\frac{\theta}{2}\right)dθdx=43Lcos(2θ)
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