(D+D'-2)Z = 0
Corresponding for each non-repeated factor (bD-aD'-c) general solution is taken as
ecx/bϕ(ax+by),b≠0e^{cx/b}\phi(ax+by), b \not=0ecx/bϕ(ax+by),b=0
D+D′−2=e2xϕ1(x−y)D+D'-2=e^{2x}\phi_1(x-y)D+D′−2=e2xϕ1(x−y)
Answer: z=e2xϕ1(x−y)z=e^{2x}\phi_1(x-y)z=e2xϕ1(x−y)
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