Question #160630

(D+D'-2)Z = 0


1
Expert's answer
2021-02-04T07:35:13-0500

Corresponding for each non-repeated factor (bD-aD'-c) general solution is taken as

ecx/bϕ(ax+by),b0e^{cx/b}\phi(ax+by), b \not=0

D+D2=e2xϕ1(xy)D+D'-2=e^{2x}\phi_1(x-y)

Answer: z=e2xϕ1(xy)z=e^{2x}\phi_1(x-y)


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