(D+D'-2)Z = 0
Corresponding for each non-repeated factor (bD-aD'-c) general solution is taken as
"e^{cx\/b}\\phi(ax+by), b \\not=0"
"D+D'-2=e^{2x}\\phi_1(x-y)"
Answer: "z=e^{2x}\\phi_1(x-y)"
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