Question #154340

x - 1 + Ce-x

1
Expert's answer
2021-01-11T16:54:24-0500

y=x−1+Ce−xy′=1−Ce−xy′+y=1−Ce−x+(x−1+Ce−x)y′+y=xy′=x−yy=x-1+Ce^{-x}\\ y'=1-Ce^{-x}\\ y'+y=1-Ce^{-x}+(x-1+Ce^{-x})\\ y'+y=x\\ y'=x-y


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