Area of enclosed by the ordinates x=a, x=b, y=f(x) curve and x-axis
= "\\int_a^bf(x)dx"
In the given problem one ordinate is fixed at (a,0) and other ordinate is at variable position (t,0)
So area will be "\\int_a^tf(x)dx"
shown in attached figure.
By the problem
"\\int_a^tf(x)dx = C(t-a)" , C = constant
Differentiating both sides
"\\frac{d}{dt} \\int_a^tf(x)dx = \\frac{d}{dt} [C(t-a)]"
=> f(t) = C
Replacing t by x we get
f(x) = C, C is a constant
Therefore equation of curve is y = C, i.e. y = constant
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