Given (2xy−y)dx−xdy=0(2\sqrt{x}y - y)dx - xdy =0(2xy−y)dx−xdy=0
Using seperation of variables method we have that:
y(2x−1)dx=xdyy(2\sqrt{x} - 1)dx = xdyy(2x−1)dx=xdy
Rearranging the equation we have that:
(2x−1)dxx=dyy\frac{(2\sqrt{x} - 1)dx}{x} = \frac{dy}{y}x(2x−1)dx=ydy
Taking the integral of both sides we have that:
4x−Inx+c=Iny4\sqrt{x} - Inx + c = Iny4x−Inx+c=Iny
which is the general solution
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments