Answer to Question #144641 in Differential Equations for Joe

Question

d²z/dx²=sin y, solve it by 2 order integration

Answer 1

Integrate with respect x

$\frac{dz}{dx}=siny \times x + c_1$

$dz = siny \times xdx +c_1dx$

Again integrate

$z = siny\frac{x^2}{2} +c_1x+c$