Question #143647
For the IVP, dy/dx= f(x,y), y(x0)= y0, the continuity of f(x,y) and ∂f/∂y guarantees the unique solution of the problem.
True or false with full explanation
1
Expert's answer
2020-11-11T12:28:26-0500

Existence and Uniqueness of Solutions

Theorem: Let the function ff and f/y\partial f/\partial y be continuous in some rectangle α<x<β,γ<y<δ,\alpha<x<\beta, \gamma<y<\delta, containing the point (x0,y0).(x_0, y_0). Then, in some interval x0n<x0<x0+hx_0-n<x_0<x_0+h contained in α<x<β\alpha<x<\beta there is a unique solution y=φ(x)y=\varphi(x) of the initial value problem


dy/dx=f(x,y),y(x0)=y0dy/dx=f(x, y), y(x_0)=y_0

The statement is true.


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