y=(x-c1)2+c2x3==
We know that (a±b)2=a2±2ab+b2(a \pm b)^2 = a^2 \pm 2ab +b^2(a±b)2=a2±2ab+b2. Then
y=(x−c1)2+c2x3=c12−2c1x+x2+c2x3y = (x -c_1)^2 +c_2 x^3 = c_1^2 - 2c_1 x +x^2 +c_2x^3y=(x−c1)2+c2x3=c12−2c1x+x2+c2x3
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