"\\displaystyle\n(y+\\cos{x})\\mathrm{d}x+(x+\\sin{y})\\mathrm{d}y=0\\\\\n\nM = y + \\cos{x}\\\\\n\n\\frac{\\partial M}{\\partial y} = 1\\\\\n\nN = x + \\sin{y}\\\\\n\n\\frac{\\partial N}{\\partial x} = 1\\\\\n\n\n\\textsf{Therefore, since}\\, \\frac{\\partial M}{\\partial y} = \\frac{\\partial N}{\\partial x}, \\\\\n\\textsf{the differential equation is exact.}"
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