Question #140386
Q\Determine the following ODEs are exact or not? Why?
(y+cosx)dx+(x+siny)dy=0
1
Expert's answer
2020-10-27T19:28:31-0400

(y+cosx)dx+(x+siny)dy=0M=y+cosxMy=1N=x+sinyNx=1Therefore, sinceMy=Nx,the differential equation is exact.\displaystyle (y+\cos{x})\mathrm{d}x+(x+\sin{y})\mathrm{d}y=0\\ M = y + \cos{x}\\ \frac{\partial M}{\partial y} = 1\\ N = x + \sin{y}\\ \frac{\partial N}{\partial x} = 1\\ \textsf{Therefore, since}\, \frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}, \\ \textsf{the differential equation is exact.}


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