Question #140383
Q\Determine the following ODEs are exact or not? Why?
(2xy)dx+2y^2dy=0
1
Expert's answer
2020-10-26T20:04:21-0400

Differential equation Mdx+Ndy=0Mdx+Ndy=0 is exact if and only if My=Nx\frac{\partial M }{\partial y}=\frac{\partial N }{\partial x}.

My=2x\frac{\partial M }{\partial y}=2x

Nx=2y2.\frac{\partial N }{\partial x}=2y^2.

ODE is not exact.


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