Solution :
"y'(x) = \\frac{e^{2x}}{2} - \\frac{3 y(x)}{2}\\\\"
Find the integration factor "\\mu=e^\\frac{3x}{2}"
Put the equation in the form ("(\\mu(x)*y)'=\\mu(x)q(x):\\,(e^\\frac{3x}{2}y)'= \\frac{e^{\\frac{7x}{2}}}{2}"
Solve: "(e^{\\frac{3x}{2}}y)'= \\frac{e^{\\frac{7x}{2}}}{2}"
"y(x) = \\frac{c_1}{e^\\frac{3x}{2}} + \\frac{e^{2 x}}{7}"
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