Every continuous function ... Satisfy a Lipschitz consution
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Expert's answer
2020-10-12T17:23:18-0400
"f(x)=x^2." Its a continuous function. Now if it satisfies Lipschitz condition, then "|f(x)-f(y)|\\leq k|x-y|" for some "k>0." We take "x=2k, y=0" . Then "|f(x)-f(y)|=|x^2-y^2|=|x+y||x-y|=2k|x-y|>k|x-y|" . Hence doesn't stisfy Lipschitz condition.
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