Question #135846
The differential equation of a family of tangent lines to the parabola y=x^2, given by 2xt=y+t, t being a parameter,4(y-xdy/dx)+(dy/dx)^2=0.
True or false with statement
1
Expert's answer
2020-10-01T14:09:03-0400

The parametric form of the given equation is x=t,y=t2.x=t, y=t^2.

The equation of any tangent at tt  is 2xt=y+t2.2xt=y+t^2.

Differentiating, we get 2t=dy/dx2t=dy/dx

Putting this value in the equation of tangent, we have 


x(dy/dx)=y+1/4(dy/dx)2x(dy/dx)=y+1/4(dy/dx)^2

4(yx(dy/dx))+(dy/dx)2=04(y-x(dy/dx))+(dy/dx)^2=0

True.



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