The given equation is
y=tan(x+a)
we can write the above equation as
"tan^{-1}y=x+a"
differentiate both sides with respect to x
"\\frac{1}{1+y^2}\\frac{dy}{dx}=1"
"\\frac{dy}{dx}=1+y^2"
"y'-y^2-1=0"
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