The given equation is
y=tan(x+a)
we can write the above equation as
tan−1y=x+atan^{-1}y=x+atan−1y=x+a
differentiate both sides with respect to x
11+y2dydx=1\frac{1}{1+y^2}\frac{dy}{dx}=11+y21dxdy=1
dydx=1+y2\frac{dy}{dx}=1+y^2dxdy=1+y2
y′−y2−1=0y'-y^2-1=0y′−y2−1=0
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments