Question #12715

Solve differential equation dy/dx=y(y-1)

Expert's answer

Solve the separable equation dy(x)dx=(y(x)1)y(x)\frac{dy(x)}{dx} = (y(x) - 1)y(x) :

Divide both sides by (y(x)1)y(x)(y(x) - 1)y(x) :


dy(x)dx(y(x)1)y(x)=1\frac {\frac {d y (x)}{d x}}{(y (x) - 1) y (x)} = 1


Integrate both sides with respect to xx :


dy(x)dx(y(x)1)y(x)dx=1dx\int \frac {\frac {d y (x)}{d x}}{(y (x) - 1) y (x)} d x = \int 1 d x


Evaluate the integrals:

log(y(x)+1)log(y(x))=x+c1\log (-y(x) + 1) - \log (y(x)) = x + c_1 , where c1c_{1} is an arbitrary constant.

Solve for y(x)y(x) :


y(x)=1ex+c1+1y (x) = \frac {1}{e ^ {x + c _ {1}} + 1}


Simplify the arbitrary constant:


y(x)=1c1ex+1y (x) = \frac {1}{c _ {1} e ^ {x} + 1}

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS