"L(\\sh(at))=\\dfrac{a}{p^2-a^2}\\newline\n\\dfrac{e^{-5s}}{s^2-25}=\\dfrac{1}{5}e^{-5s}\\dfrac{5}{p^2-25}\\newline\nL^{-1}(\\dfrac{e^{-5s}}{s^2-25})=\\dfrac{1}{5}\\sh(5t)\\eta(t-5)\\newline\nWhere \\space \\eta(t) \\space is \\space a\\space Heaviside's function\\newline\n\\newline\n2. f(t)=H_{0,6}(t)=\\eta(t)-\\eta(t-6)\\newline\nL(f(t))=\\dfrac{1}{s}-e^{-6s}\\dfrac{1}{s}=\\dfrac{1-e^{-6s}}{s}"
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Dear B. Rama krishna. What should be done in your question. Please use the panel for submitting a new question.
(2s-5) /(9s*s-25)
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