Question

What is the generation time (min) of 102 E. Coli cell (CFU/g) growing logarithmically for 6 h produce 1.7 x 106 CFU/g?

Answer 1

SInce, number of generation in time t is

$$n=\dfrac{\ln(N)-\ln(N_o)}{\ln2}$$

Thus,

$$n=\dfrac{\ln(1.7\times10^6)-\ln(10^2)}{\ln2}=14$$

Hence, genration time is $14/360\approx0.039$ generation/min