Find the solution of the initial-value problem and determine its interval of existence (i.e domain of the resulting function y). (i) dy dt = 1+t2 t , (ii) (t + 1)dy y(t = 1) = 0. dt = 1−y, y(t = 0) = 3. [Hint: Let A = −(±e−C).]
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Expert's answer
2020-06-29T19:19:31-0400
i).Given,
"\\frac{dy}{dt}=1+t^2"
Initial condition is not given,thus we are solving the general solution.
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