"\\frac {dy}{dx} + \\frac {x}{1+x} y = e^x"
Comparing with "\\frac {dy}{dx} + Py = Q" we get
P = "\\frac {x}{1+x}" = "\\frac {x}{x+1}" and Q = ex
So integrating factor is
"e^{\\int Pdx}" = "e^{\\int \\frac {x}{x+1}dx}" = "e^{\\int \\frac {x+1-1}{x+1}dx}"
= "e^{\\int ( \\frac {x+1}{x+1} - \\frac {1}{x+1})dx}"
= "e^{\\int ( 1 - \\frac {1}{x+1})dx}"
= "e^{x - ln(1+x)}"
= "\\frac {e^x}{e^{ln(1+x)}}"
= "\\frac {e^x}{1+x}"
"\\mathbf {Answer}"
The integrating factor is "\\frac {e^x}{1+x}"
Comments
Leave a comment