"y'=-2c_1sin2x+2c_2cos2x"
"y''=-4c_1cos2x-4c_2sin2x"
Then:
"y'' + 4y =-4c_1cos2x-4c_2sin2x+ 4c_1 cos 2x +4 c_2 sin 2x=0"
Answer: C. "y'' + 4y = 0"
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