Question #122487

A 100-volt electromotive force is applied to an RC-series circuit in which the resistance is 500 ohms and the capacitance is 10^−4 farad. Find the charge q(t) on the capacitor if q(0) = 0.


q(t) = _____


Find the current i(t).

i(t) = ____

Expert's answer

The Differential equation for RC-series circuit is

Rdqdt+1Cq=E(t)R \frac{dq}{dt} + \frac{1}{C} q = E(t) .

Now, R=500R = 500 ohm, C = 10−410^{-4 } F, E(t) = 100 V.

So, 500dqdt+104q=100  ⟹  dqdt+20q=0.2500 \frac{dq}{dt} + 10^4 q = 100 \implies \frac{dq}{dt} + 20 q = 0.2

This is standard first-order differential equation.

So, Integrating factor = e∫20dt=e20te^{\int20dt} = e^{20t} .

Hence solution is qe20t=∫(0.2)e20tdt+cq e^{20t} = \int(0.2)e^{20t} dt + c

  ⟹  qe20t=(0.2)e20t20+c=0.01e20t+c\implies qe^{20t} = (0.2) \frac{e^{20t} }{20}+ c =0.01 e^{20t} +c

Now, q(0)=0  ⟹  0.01+c=0  ⟹  c=−0.01q(0)=0 \implies 0.01 + c = 0\implies c = -0.01

  ⟹  qe20t=0.01(e20t−1)  ⟹  q=0.01(e20t−1)e20t=0.01(1−e−20t)\implies qe^{20t} = 0.01(e^{20t}-1) \\ \implies q = \frac{0.01(e^{20t}-1)}{e^{20t}} = 0.01 (1-e^{-20t})

And current i(t)=dqdt=0.2e−20ti(t) = \frac{dq}{dt} = 0.2 e^{-20t}


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