We can form the PDE by eliminating f and g from
z=f(x+ay)+g(x-ay) ....(1)
Differentiate (1) w.r.t. x and y ,we get
p=f'(x+ay)+g'(x-ay) .....(2)
q=f'(x+ay).a+g'(x-ay).(-a) ...(3)
Now differentiate (2) &(3) w. r. t to x and y respectively
r=f"(x+ay)+g"(x-ay)
t=f"(x+ay).a2+g"(x-ay)(-a)2
Now t= a2[ f"(x+ay)+g"(x-ay)]
Hence , t=a2.r
This is the required PDE
Ans . : t=a2.r
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