We will use the Chain Rule for the following functions: "v = (2t+3)^4 = f(g(t))", where "f(t) = t^4, g(t) = 2t + 3" .
Since "\\frac{df}{dt} = 4t^3" and "\\frac{dg}{dt} = 2" , by the chain rule, we obtain that:
"a = \\frac{dv}{dt} = \\frac{df}{dg} \\frac{dg}{dt} = 4(2t+3)^3 \\cdot 2 = 8(2t+3)^3"
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