It is false.
If we take f(u)=0f(u)=0f(u)=0, then we obtain z=−yz=-yz=−y.
Then dzdx=0\frac{dz}{dx}=0dxdz=0, dzdy=−1\frac{dz}{dy}=-1dydz=−1 and z2=y2z^2=y^2z2=y2.
Functions 0+(−1)=−10+(-1)=-10+(−1)=−1 and y2y^2y2 are not equal.
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