Question

Obtain the differential equation associated with y= Be^x with A&B being arbitrary constants

Answer 1

The given equation should be $y=Be^{x} \implies y'=Be^{x} \implies B=y'/e^{x}$

$\implies y=y'e^x/e^x=y'$

Thus, $dy/dx-y=0$ is the differential equation, associated with the given equation.