Solution. The characteristic equation for a ordinary differential equation
k2+k+1=0 Solve the quadratic equation
D=12−4×1×1=−3<0 Roots of the equation
k1=2−1−3i
k2=2−1+3i Therefore the solution for a ordinary differential equation
y=e2−x(C1sin(23x)+C2cos(23x)) where C1 and C2 are constants.
Answer.
y=e2−x(C1sin(23x)+C2cos(23x)) where C1 and C2 are constants.
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