Determine the Fourier transform of the function
f(t)=1-t. 0 ≤t≤1
1+t. -1≤t≤0
0. Otherwise
1
2019-03-02T11:12:16-0500
f^(k)=R∫f(t)e−2πiktdt
=−1∫0(1+t)e−2πiktdt+0∫1(1−t)e−2πiktdt
=4π2k22πik−e2πik+1+4π2k22πik+e2πik−1
=π2k2sin2(πk)
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