Question #82501

simplify this complex number
cos3x + jsin3x / cosx + jsinx

Expert's answer

Answer on Question #82501 – Math – Complex Analysis

Question

Simplify this complex number


(cos3x+jsin3x)/(cosx+jsinx)(\cos 3x + \text{jsin}3x) / (\cos x + \text{jsin}x)

Solution

cos3x+jsin3xcosx+jsinx=cos(3xx)+jsin(3xx)=cos2x+jsin2x.\frac{\cos 3x + \text{jsin}3x}{\cos x + \text{jsin}x} = \cos(3x - x) + \text{jsin}(3x - x) = \cos 2x + \text{jsin}2x.


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