Question #67556

Find the image of the half plane y>1 under the transformation w=(1-i)z
1

Expert's answer

2017-04-26T14:36:07-0400

Answer on Question #67556 – Math – Complex Analysis

Question

Find the image of the half plane y>1y > 1 under the transformation w=(1i)zw = (1 - i)z.

Solution

z=x+iy,z = x + iy,


where


y>1y > 1w=(1i)z=(1i)(x+iy)=xix+iy+y=x+y+i(yx)w = (1 - i)z = (1 - i)(x + iy) = x - ix + iy + y = x + y + i(y - x)w=u+iv,w = u + iv,


where


{u=x+yv=yx\left\{ \begin{array}{l} u = x + y \\ v = y - x \end{array} \right.


Add the first and the second equations of the system


u+v=x+y+yx=2y>2,u + v = x + y + y - x = 2y > 2,


because


y>1.y > 1.


The image will be the half plane u+v>2u + v > 2.

If we assume that w=x+iyw = x + iy, the image will be the half plane x+y>2x + y > 2.

**Answer**: If we assume that w=x+iyw = x + iy, the image will be the half plane x+y>2x + y > 2.

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