Question #58320

The polar form of the complex number z = x + iy is given by …………….

Expert's answer

Answer on Question #58320 – Math – Complex Analysis

Question

The polar form of the complex number


z=x+iyz = x + iy


is given by

Solution

The algebraic form of the complex number zz is z=x+iyz = x + iy.

The polar form of the complex number zz is given by


z=A(cosφ+sinφ).z = A(\cos\varphi + \sin\varphi).


Relationship between the polar and algebraic forms of a complex number:


A=x2+y2,A = \sqrt{x^2 + y^2},φ={arccosxx2+y2,y0,x2+y2>0,arccosxx2+y2,y<0,x2+y2>0,undefined,x2+y2=0;\varphi = \begin{cases} \arccos \dfrac{x}{\sqrt{x^2 + y^2}}, & y \geq 0, \sqrt{x^2 + y^2 > 0}, \\ -\arccos \dfrac{x}{\sqrt{x^2 + y^2}}, & y < 0, \sqrt{x^2 + y^2} > 0, \\ \text{undefined}, & \sqrt{x^2 + y^2} = 0; \end{cases}


or


φ={arctanyx,x>0,+π2,x=0,y>0,π2,x=0,y<0,arctanyx+π,x<0,y0,arctanyxπ,x<0,y<0.\varphi = \begin{cases} \arctan\dfrac{y}{x}, & x > 0, \\ +\dfrac{\pi}{2}, & x = 0, y > 0, \\ -\dfrac{\pi}{2}, & x = 0, \quad y < 0, \\ \arctan\dfrac{y}{x} + \pi, x < 0, y \geq 0, \\ \arctan\dfrac{y}{x} - \pi, x < 0, y < 0. \end{cases}


Relationship between the algebraic and polar forms of a complex number:


x=Acosφ,y=Asinφ.x = A\cos\varphi, y = A\sin\varphi.


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