Question #58298

Let
z=−3+i7√
z=−3+i7
, then
tanθ=

Expert's answer

Answer on Question #58298 – Math – Complex Analysis

Question

Let


z=3+i7z = -3 + i7\sqrt{}z=3+i7,z = -3 + i7,


then


tanθ=\tan\theta=

Solution

z=x+iy=3+7itanθ=yx=73=73;z = x + iy = -3 + \sqrt{7}i \rightarrow \tan\theta = \frac{y}{x} = \frac{\sqrt{7}}{-3} = -\frac{\sqrt{7}}{3};z=x+iy=3+7itanθ=yx=73=73.z = x + iy = -3 + 7i \rightarrow \tan\theta = \frac{y}{x} = \frac{7}{-3} = -\frac{7}{3}.


Answer: 73;73-\frac{\sqrt{7}}{3}; -\frac{7}{3}

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