Answer on Question #58285 – Math – Complex Analysis
Question
Let z∈Cz \in \mathbb{C}z∈C, then ∣z∣∈⋯|z| \in \cdots∣z∣∈⋯
Solution
If z∈Cz \in \mathbb{C}z∈C, then ∣z∣∈R|z| \in \mathbb{R}∣z∣∈R. Indeed, the modulus of any complex number z=a+biz = a + biz=a+bi is defined by ∣z∣=a2+b2|z| = \sqrt{a^2 + b^2}∣z∣=a2+b2, which is already a real number.
Answer: ∣z∣∈R|z| \in \mathbb{R}∣z∣∈R
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