Answer on Question #50129, Math, Complex Analysis
Given:
n=2∑∞2nncosn+isinn
Decide:
if these series is convergent or divergent
Solution:
an=(cosn+isinn)2n31=(ein)2n31=ei⋅2n3arg(ein)+2πkk∈Zarg(ein)=n∣an∣=1
we can use the fact
n→∞liman=0⇔n→∞lim∣an∣=0
we obtain
limn→∞∣an∣=1=0 the necessary condition of convergence of series is not executed, so the series is divergent.
Answer: divergent
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