Answer to Question #50054 in Complex Analysis for Alyaa
Find the Limit ( value or infinity or zero )
[ (n+1 )^ square root of {n+1} ] / [n ^ square root of {n} ]
or i can say
Limit
[ (n+1 )^ ( {n+1}^ {1/2} ) ] / [ n ^ ({n}^ {1/2} ) ]
as n: infinity
1
2014-12-19T02:54:22-0500
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