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Answer to Question #49481 in Complex Analysis for AZIZ
Question #49481
Test series for convergence:
1) [ i^n/(2^(n+2)) ]
2) (n!)^2/e^n
3) 1/[root(i+n)]^n
4) e^(i coshn)
5) [n+i/(4^n)]
1) [ i^n/(2^(n+2)) ]
2) (n!)^2/e^n
3) 1/[root(i+n)]^n
4) e^(i coshn)
5) [n+i/(4^n)]
Expert's answer
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#340153 on Dec 2023
#340153 on Dec 2023
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