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Question #346624
Convert (1−i)/2 into trigonometric form
Expert's answer
z
=
1
2
−
1
2
i
z=\dfrac{1}{2}-\dfrac{1}{2}i
z
=
2
1
−
2
1
i
Quadrant IV
r
2
=
(
1
2
)
2
+
(
−
1
2
)
2
=
1
2
r^2=(\dfrac{1}{2})^2+(-\dfrac{1}{2})^2=\dfrac{1}{2}
r
2
=
(
2
1
)
2
+
(
−
2
1
)
2
=
2
1
r
=
2
2
,
θ
=
tan
−
1
(
−
(
1
/
2
)
1
/
2
)
+
2
π
=
7
π
4
r=\dfrac{\sqrt{2}}{2}, \theta=\tan^{-1}(\dfrac{-(1/2)}{1/2})+2\pi=\dfrac{7\pi}{4}
r
=
2
2
,
θ
=
tan
−
1
(
1/2
−
(
1/2
)
)
+
2
π
=
4
7
π
(
2
2
,
7
π
4
)
(\dfrac{\sqrt{2}}{2}, \dfrac{7\pi}{4})
(
2
2
,
4
7
π
)
Or
r
=
2
2
,
θ
=
tan
−
1
(
−
(
1
/
2
)
1
/
2
)
+
π
=
3
π
4
r=\dfrac{\sqrt{2}}{2}, \theta=\tan^{-1}(\dfrac{-(1/2)}{1/2})+\pi=\dfrac{3\pi}{4}
r
=
2
2
,
θ
=
tan
−
1
(
1/2
−
(
1/2
)
)
+
π
=
4
3
π
(
−
2
2
,
3
π
4
)
(-\dfrac{\sqrt{2}}{2}, \dfrac{3\pi}{4})
(
−
2
2
,
4
3
π
)
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#340153
on Dec 2023
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