If w=3iz-z2 given that z=x+iy, find w2 in terms of xand y.
Select one:
A x4+y4+2x2y2-6x2y-6y3-9x2-9y2
B x4+y4+2x2y2-6x2y-6y3+9x2+9y2
C x4+y4+2x2y2-6x2y-6y3+9x2-9y2
D x4-y4+2x2y2-6x2y-6y3+9x2+9y2
∣w∣2=∣z(z−3i)∣2=∣z∣2∣z−3i∣2==(x2+y2)(x2+(y−3)2)==x4+x2(y2+(y−3)2)+y2(y−3)2==x4+y4+2x2y2−6x2y−6y3+9x2+9y2B is correct\left| w \right|^2=\left| z\left( z-3i \right) \right|^2=\left| z \right|^2\left| z-3i \right|^2=\\=\left( x^2+y^2 \right) \left( x^2+\left( y-3 \right) ^2 \right) =\\=x^4+x^2\left( y^2+\left( y-3 \right) ^2 \right) +y^2\left( y-3 \right) ^2=\\=x^4+y^4+2x^2y^2-6x^2y-6y^3+9x^2+9y^2\\B\,\,is\,\,correct∣w∣2=∣z(z−3i)∣2=∣z∣2∣z−3i∣2==(x2+y2)(x2+(y−3)2)==x4+x2(y2+(y−3)2)+y2(y−3)2==x4+y4+2x2y2−6x2y−6y3+9x2+9y2Biscorrect
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