How do you write the residue at z=∞ where f(z) = 1/z^3+z^5?
A)-2
B)-1
C)1
D)0
To calculate the residue at infinity we have the following relation :
"Res_\\infty f(z) = -Res_0 g(\\xi)" with "g(\\xi)=f(1\/\\xi)".
Therefore, we consider the residue of "\\xi^3+1\/\\xi^5" at zero.
We can calculate it directly (for example, we know that the residue is the coefficient before "1\/\\xi" in the Laurent series) and we find that "Res_0 g(\\xi)=0" and therefore "Res_\\infty f(z)=0" , the correct answer is D.
A faster way to obtain this result could be using the fact that the sum of residues of a meromorphic function (counting the residue at the infinity) is zero. The only residue of "f" in "\\mathbb{C}" is the residue at zero and it is null.
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