Find an analytic continuation ππ‘ ,π·π‘ : 0 β€ π‘ β€ 1 of
π0
,π·0
along πΎ and show that π1
1 = π0
1
Where π·0 = π΅ 1 , 1 πππ π0
is restriction of the principal
branch of βπ§ to π·0
. πΎ (π‘ )= π^
2πππ‘ πππ π π‘ = π^
4πππ‘
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