Question #254161

Express z 1⁄4 e1þj=2 in the form a þ j


1
Expert's answer
2021-10-21T12:59:16-0400

zejb/4=2ze^{jb}/4=2

(a+jb)(cosb+jsinb)=8(a+jb)(cosb+jsinb)=8

acosbbsinb+j(asinb+bcosb)=8acosb-bsinb+j(asinb+bcosb)=8

asinb+bcosb=0asinb+bcosb=0

a=bcosb/sinba=-bcosb/sinb

bcos2b/sinbbsinb=8-bcos^2b/sinb-bsinb=8

b=8sinbb=-8sinb


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