A complex number z satisfies the equation
z^2\:=3+4i.
Which of the following is true about z?
Taking into account that
3+4i=4−1+4i=22+4i+i2=(2+i)2,3+4i=4-1+4i=2^2+4i+i^2=(2+i)^2,3+4i=4−1+4i=22+4i+i2=(2+i)2,
we conclude that z2=(2+i)2,z^2=(2+i)^2,z2=(2+i)2, and hence z=±(2+i).z=\pm (2+i).z=±(2+i).
Answer: 2
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