Evaluate integral of (z-3)^4 where c is the circle |z-3|=4
By Cauchy's integral theorem:
∮Lf(z)dz=0\oint_Lf(z)dz=0∮Lf(z)dz=0
So:
∮∣x−3∣=4(z−3)4dz=0\oint_{|x-3|=4}(z-3)^4dz=0∮∣x−3∣=4(z−3)4dz=0
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments