Answer to Question #190076 in Complex Analysis for Piyush

Question

Mod of 2+3i

Answer 1

Recall that the modulus of the number $z=a+bi$ is $|z|=\sqrt{a^2+b^2}$ . In our case,

$$|2+3i|=\sqrt{2^2+3^2}=\sqrt{4+9}=\sqrt{13}.$$