Question #18790

Suppose p is a polynomial with n distinct real roots. Show that p' has
at least (n-1) distinct real roots.
1

Expert's answer

2012-11-16T06:17:37-0500

Conditions

Suppose pp is a polynomial with nn distinct real roots. Show that pp' has at least n1n-1 distinct real roots.

Solution

Let's use Rolle's Theorem. It claims that for differentiable functions with two points with an equal value, their derivative has a root between these points.

The polynomial is a differentiable function, and as we have nn roots, so we have n1n-1 intervals, where at two distinct points we have equal values (zero, as they are roots).

We have the following n-1 intervals


(α1,α2),(α2,α3),,(αn1,αn)(\alpha_1, \alpha_2), (\alpha_2, \alpha_3), \dots, (\alpha_{n-1}, \alpha_n)P(α1)=P(α2)==P(αn)=0P(\alpha_1) = P(\alpha_2) = \dots = P(\alpha_n) = 0


In each interval by Rolle's Theorem we have 1 root for derivative function. Totally n1n-1 roots. And the proof is done.

Q.E.D.

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