Question #15160

In a management trainee program, 80% female and 20% male. 90% of the females went to college. 78% of the males went to college. A management trainee is selected at random. What is the probability that the person selected is a female who did NOT go to college?

Expert's answer

Question #15160In a management trainee program,0. 80 female and 0.20 male.0. 90 of the females went to college. 0.78 of the males went to college. A management trainee is selected at random. What is the probability that the person selected is a female who did NOT go to college? .

Solution. Denote by FF the event that selected at random person is female, and the same thing for MM. The condition implies that P(F)=1−P(M)=0.8\mathsf{P}(F)=1-\mathsf{P}(M)=0.8.Denote by AA the event that person selected at random did not go to the college, hence P(A∣F)=0.1\mathsf{P}(A|F)=0.1 and P(A∣M)=0.12\mathsf{P}(A|M)=0.12 We are interested in the probability P(F∩A)=P(A∣F)P(F)=0.1⋅0.8=0.08\mathsf{P}(F\cap A)=\mathsf{P}(A|F)\mathsf{P}(F)=0.1\cdot 0.8=0.08.

Answer 0.08.

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