5−i=26eiϕ5-i=\sqrt{26}e^{i\phi}5−i=26eiϕ , ϕ=sin−1(−126)\phi=\sin^{-1}({-\frac{1}{\sqrt{26}}})ϕ=sin−1(−261)
if z5=5−iz^5=5-iz5=5−i then
z=26110eiϕ5+2kπ5,k=0,1,2,3,4z=26^{\frac{1}{10}}e^{\frac{i\phi}{5}+\frac{2k\pi}{5}} , k=0, 1, 2, 3, 4z=26101e5iϕ+52kπ,k=0,1,2,3,4.
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